代码拉取完成,页面将自动刷新
'''Tower of Hanoi is a mathematical puzzle where we have three rods and n disks. The objective of the puzzle is to move
the entire stack to another rod, obeying the following simple rules:
1) Only one disk can be moved at a time.
2) Each move consists of taking the upper disk from one of the stacks and placing it on top of another stack i.e. a disk
can only be moved if it is the uppermost disk on a stack.
3) No disk may be placed on top of a smaller disk.
APPROACH:
Take an example for 2 disks :
Let rod 1 = 'SOURCE', rod 2 = 'TEMPORARY', rod 3 = 'DESTINATION'.
Step 1 : Shift first disk from 'SOURCE' to 'TEMPORARY'.
Step 2 : Shift second disk from 'SOURCE' to 'DESTINATION'.
Step 3 : Shift first disk from 'TEMPORARY' to 'DESTINATION'.
The pattern here is :
Shift 'n-1' disks from 'SOURCE' to 'TEMPORARY'.
Shift last disk from 'SOURCE' to 'DESTINATION'.
Shift 'n-1' disks from 'TEMPORARY' to 'DESTINATION'.
'''
def toh(n,s,t,d):
if n==1:
print(s,'-->',d)
return
toh(n-1,s,d,t)
print(s,'-->',d)
toh(n-1,t,s,d)
if __name__=="__main__":
while 1:
n = int(input('''Enter number of disks:'''))
if n<0:
print("Try Again with a valid input")
continue
elif n==0:
break
toh(n,'Source','Temporary','Destination')
print('ENTER 0 TO EXIT')
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。