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tik_tak.py 2.86 KB
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Jérôme Krell 提交于 2019-10-10 14:22 . Reformat Code by PyCharm-Community
# Tik-tak game
board = ["anything", 1, 2, 3, 4, 5, 6, 7, 8, 9]
switch = "p1"
j = 9
print("\n\t\t\tTIK-TAC-TOE")
def print_board():
# import os
# os.system('cls')
print("\n\n")
print(" | |")
print("", board[1], " | ", board[2], " | ", board[3])
print("____|_____|____")
print(" | |")
print("", board[4], " | ", board[5], " | ", board[6])
print("____|_____|____")
print(" | |")
print("", board[7], " | ", board[8], " | ", board[9])
print(" | |")
def enter_number(p1_sign, p2_sign):
global switch
global j
k = 9
while (j):
if k == 0:
break
if switch == "p1":
p1_input = int(input("\nplayer 1 :- "))
if p1_input <= 0:
print("chose number from given board")
else:
for e in range(1, 10):
if board[e] == p1_input:
board[e] = p1_sign
print_board()
c = checkwin()
if c == 1:
print("\n\n Congratulation ! player 1 win ")
return
switch = "p2"
j -= 1
k -= 1
if k == 0:
print("\n\nGame is over")
break
if k == 0:
break
if switch == "p2":
p2_input = int(input("\nplayer 2 :- "))
if p2_input <= 0:
print("chose number from given board")
# return
else:
for e in range(1, 10):
if board[e] == p2_input:
board[e] = p2_sign
print_board()
w = checkwin()
if w == 1:
print("\n\n Congratulation ! player 2 win")
return
switch = "p1"
j -= 1
k -= 1
def checkwin():
if board[1] == board[2] == board[3]:
return 1
elif board[4] == board[5] == board[6]:
return 1
elif board[7] == board[8] == board[9]:
return 1
elif board[1] == board[4] == board[7]:
return 1
elif board[2] == board[5] == board[8]:
return 1
elif board[3] == board[6] == board[9]:
return 1
elif board[1] == board[5] == board[9]:
return 1
elif board[3] == board[5] == board[7]:
return 1
else:
print("\n\nGame continue")
def play():
print_board()
p1_sign = input("\n\nplayer 1 chose your sign [0/x] = ")
p2_sign = input("player 2 chose your sign [0/x] = ")
enter_number(p1_sign, p2_sign)
print("\n\n\t\t\tDeveloped By :- UTKARSH MATHUR")
if __name__ == "__main__":
play()
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