1 Star 0 Fork 0

fanyangchu/PythonCode

加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
克隆/下载
HangMan Game 2.48 KB
一键复制 编辑 原始数据 按行查看 历史
Lovesh Kumrawat 提交于 2020-10-04 12:21 . HangMan Game
# Program for HangMan Game.
import random, HangMan_Includes as incl
while True:
chances=6
inp_lst=[]
result_lst=[]
name=random.choice(incl.names).upper()
# print(name)
[result_lst.append('__ ') for i in range(len(name))]
result_str=str().join(result_lst)
print(f'\nYou have to Guess a Human Name of {len(name)} Alphabets:\t{result_str}')
print(incl.draw[0])
while True:
if result_str.replace(' ','')==name:
print(f'\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Correct Answer: {name} ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
print(incl.won+'\a')
break
inp=input('\nGuess an Alphabet or a Sequence of Alphabets: ').upper()
if inp in inp_lst:
print('......................................................................Already Tried')
continue
else:
inp_lst.append(inp)
t=0
indx=[]
if inp in name:
temp=name
while temp!='':
if inp in temp:
indx.append(t+temp.index(inp))
t=temp.index(inp)+1
temp=temp[t:]
else:
break
for j in range(len(indx)):
for i in range(len(inp)):
result_lst[indx[j]]=inp[i]+' '
indx[j]+=1
i+=1
result_str=str().join(result_lst)
print('\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Excellent~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
print(f'\nYou have to Guess a Human Name of {len(name)} Alphabets:\t{result_str}\n')
print('Tried Inputs:',tuple(sorted(set(inp_lst))))
else:
print('\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Try Again!!!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
print(f'\nYou have to Guess a Human Name of {len(name)} Alphabets:\t{result_str}\n')
print(incl.draw[chances])
chances=chances-1
if chances!=0:
print('Tried Inputs:',tuple(sorted(set(inp_lst))))
print(f'\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~You were left with {chances} Chances~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
else:
print(f'\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Correct Answer: {name} ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
print(incl.lose+'\a')
break
try:
if int(input('To play the Game Again Press "1" & "0" to Quit: '))!=1:
exit('\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Thank You~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
except:
exit('\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Thank You~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~')
马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
1
https://gitee.com/fanych/pythoncode.git
git@gitee.com:fanych/pythoncode.git
fanych
pythoncode
PythonCode
master

搜索帮助