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"""
Problem 42: https://projecteuler.net/problem=42
The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1); so
the first ten triangle numbers are:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
By converting each letter in a word to a number corresponding to its
alphabetical position and adding these values we form a word value. For example,
the word value for SKY is 19 + 11 + 25 = 55 = t10. If the word value is a
triangle number then we shall call the word a triangle word.
Using words.txt (right click and 'Save Link/Target As...'), a 16K text file
containing nearly two-thousand common English words, how many are triangle
words?
"""
# _*_ conding:UTF-8 _*_
'''
@author = Kuperain
@email = kuperain@aliyun.com
@IDE = VSCODE Python3.8.3
@creat_time = 2022/5/14
'''
LetterDict = {chr(x): x-ord('a') + 1
for x in range(ord('a'), ord('z')+1)}
LetterDict.update({chr(x): x-ord('A')+1
for x in range(ord('A'), ord('Z')+1)})
Trianglenumbers = [n*(n+1)//2 for n in range(50)]
def solution(input: str = 'p042_words.txt') -> int:
with open(input, 'r') as fp:
names = eval('['+fp.read().strip()+']')
def isTriangleword(name: str) -> int:
value = 0
for c in name:
if c not in LetterDict: # special chars, such as '-','.'
LetterDict[c] = ord(c.lower()) - ord('a')+1
value += LetterDict[c]
return value in Trianglenumbers or (
int((8*value+1)**0.5)**2 == 8*value+1)
# solve equation n(n+1) = 2value
return sum(list(map(isTriangleword, names)))
if __name__ == "__main__":
import doctest
doctest.testmod(verbose=False)
print(solution())
# 162
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