202122011104.ipynb · 崔畅/pythonHW

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{
 "cells": [
  {
   "cell_type": "markdown",
   "id": "b3ee08ac-c574-429d-866e-aa4f7d3a9a27",
   "metadata": {},
   "source": [
    "# 问题一：\n",
    "有一个这样的DNA核酸序列“AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC”\n",
    "\n",
    "请把这个核酸序列存入一个list，并数一数A、G、C、T各有多少个"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 11,
   "id": "3c69f828-6662-456a-84f2-2eb8e0f42daf",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "\n",
      "列表中A的个数为: 20\n",
      "\n",
      "列表中G的个数为: 17\n",
      "\n",
      "列表中C的个数为: 12\n",
      "\n",
      "列表中T的个数为: 21\n"
     ]
    }
   ],
   "source": [
    "string = 'AGCTTTTCATTCTGACTGCAACGGGCAATATGTCTCTGTGTGGATTAAAAAAAGAGTGTCTGATAGCAGC'\n",
    "li = [i for i in string] # 存入列表\n",
    "\n",
    "print(\"\\n列表中A的个数为:\",li.count('A'))\n",
    "print(\"\\n列表中G的个数为:\",li.count('G'))\n",
    "print(\"\\n列表中C的个数为:\",li.count('C'))\n",
    "print(\"\\n列表中T的个数为:\",li.count('T'))"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "e4ee99c7-1201-4474-b3a7-f67694a68b00",
   "metadata": {},
   "source": [
    "# 问题二：\n",
    "一个花样滑冰运动员表演后，裁判给表演内容进行评分，分数从0.25分到10分，每次增加值为0.25分。 试生成一个元组，把可能的得分存入元组，并遍历元组的每一项，打印“一个运动员可能得_____分”。"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 30,
   "id": "e6422cff-c4b0-4b9d-b564-be57e85cbdf2",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "可能得分有： (0.25, 0.5, 0.75, 1.0, 1.25, 1.5, 1.75, 2.0, 2.25, 2.5, 2.75, 3.0, 3.25, 3.5, 3.75, 4.0, 4.25, 4.5, 4.75, 5.0, 5.25, 5.5, 5.75, 6.0, 6.25, 6.5, 6.75, 7.0, 7.25, 7.5, 7.75, 8.0, 8.25, 8.5, 8.75, 9.0, 9.25, 9.5, 9.75, 10.0)\n",
      "\n",
      "一个运动员可能得0.25分\n",
      "\n",
      "一个运动员可能得0.5分\n",
      "\n",
      "一个运动员可能得0.75分\n",
      "\n",
      "一个运动员可能得1.0分\n",
      "\n",
      "一个运动员可能得1.25分\n",
      "\n",
      "一个运动员可能得1.5分\n",
      "\n",
      "一个运动员可能得1.75分\n",
      "\n",
      "一个运动员可能得2.0分\n",
      "\n",
      "一个运动员可能得2.25分\n",
      "\n",
      "一个运动员可能得2.5分\n",
      "\n",
      "一个运动员可能得2.75分\n",
      "\n",
      "一个运动员可能得3.0分\n",
      "\n",
      "一个运动员可能得3.25分\n",
      "\n",
      "一个运动员可能得3.5分\n",
      "\n",
      "一个运动员可能得3.75分\n",
      "\n",
      "一个运动员可能得4.0分\n",
      "\n",
      "一个运动员可能得4.25分\n",
      "\n",
      "一个运动员可能得4.5分\n",
      "\n",
      "一个运动员可能得4.75分\n",
      "\n",
      "一个运动员可能得5.0分\n",
      "\n",
      "一个运动员可能得5.25分\n",
      "\n",
      "一个运动员可能得5.5分\n",
      "\n",
      "一个运动员可能得5.75分\n",
      "\n",
      "一个运动员可能得6.0分\n",
      "\n",
      "一个运动员可能得6.25分\n",
      "\n",
      "一个运动员可能得6.5分\n",
      "\n",
      "一个运动员可能得6.75分\n",
      "\n",
      "一个运动员可能得7.0分\n",
      "\n",
      "一个运动员可能得7.25分\n",
      "\n",
      "一个运动员可能得7.5分\n",
      "\n",
      "一个运动员可能得7.75分\n",
      "\n",
      "一个运动员可能得8.0分\n",
      "\n",
      "一个运动员可能得8.25分\n",
      "\n",
      "一个运动员可能得8.5分\n",
      "\n",
      "一个运动员可能得8.75分\n",
      "\n",
      "一个运动员可能得9.0分\n",
      "\n",
      "一个运动员可能得9.25分\n",
      "\n",
      "一个运动员可能得9.5分\n",
      "\n",
      "一个运动员可能得9.75分\n",
      "\n",
      "一个运动员可能得10.0分\n"
     ]
    }
   ],
   "source": [
    "scores = []\n",
    "i = 0.25 # 初始值\n",
    "while i <= 10:\n",
    "    scores.append(i)\n",
    "    i += 0.25\n",
    "\n",
    "scores = tuple(scores) # 存入元组\n",
    "print('可能得分有：', scores)\n",
    "for score in scores:\n",
    "    print('\\n一个运动员可能得%s分' % score)"
   ]
  },
  {
   "cell_type": "markdown",
   "id": "5a1e89c6-6e21-4918-be19-0ba88ea0d9a7",
   "metadata": {},
   "source": [
    "# 问题三：\n",
    "\n",
    "创建一个字典，列出你所了解的地域美食，比如{'肠粉':{'城市':'广州','原料':'米'}}。 当然，你可以做的更丰富一些。 最后遍历你熟悉的美食，打印出，类似如下的句子：“肠粉是广州的一种美食，它的主要原料是米”。"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 35,
   "id": "74808f4d-ea08-42f9-8735-1985c99b0fa7",
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "肠粉是广州的一种美食，它的主要原料是米\n",
      "蛋烘糕是成都的一种美食，它的主要原料是面粉\n",
      "把子肉是济南的一种美食，它的主要原料是猪肉\n",
      "冷吃兔是自贡的一种美食，它的主要原料是兔肉\n"
     ]
    }
   ],
   "source": [
    "food_dict = {\n",
    "    '肠粉':{'城市':'广州','原料':'米'},\n",
    "    '蛋烘糕':{'城市':'成都','原料':'面粉'},\n",
    "    '把子肉':{'城市':'济南','原料':'猪肉'},\n",
    "    '冷吃兔':{'城市':'自贡','原料':'兔肉'}\n",
    "            }\n",
    "\n",
    "for food, info in food_dict.items():\n",
    "    print(food + '是' + info['城市'] + '的一种美食，它的主要原料是' + info['原料'])"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "bd756682-0a36-4b24-96e5-1dab1171acac",
   "metadata": {},
   "outputs": [],
   "source": []
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "96c8c70d-2cac-419e-807a-b93e7d98f6b4",
   "metadata": {},
   "outputs": [],
   "source": []
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "2f44c48d-9b1a-48ab-ad33-c22fd6c22324",
   "metadata": {},
   "outputs": [],
   "source": []
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "id": "eedd2225-6a85-440d-8e40-104a264970c1",
   "metadata": {},
   "outputs": [],
   "source": []
  }
 ],
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提交于 2022-04-10 10:42 . 202122011104 + 张龙

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